4x^2+2=336

Solution for 4x^2+2=336 equation:

4x^2+2=336

We move all terms to the left:

4x^2+2-(336)=0

We add all the numbers together, and all the variables

4x^2-334=0

a = 4; b = 0; c = -334;
Δ = b2-4ac
Δ = 02-4·4·(-334)
Δ = 5344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5344}=\sqrt{16*334}=\sqrt{16}*\sqrt{334}=4\sqrt{334}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{334}}{2*4}=\frac{0-4\sqrt{334}}{8}
=-\frac{4\sqrt{334}}{8}
=-\frac{\sqrt{334}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{334}}{2*4}=\frac{0+4\sqrt{334}}{8}
=\frac{4\sqrt{334}}{8}
=\frac{\sqrt{334}}{2}
$